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(H)=-16H^2-10H+84
We move all terms to the left:
(H)-(-16H^2-10H+84)=0
We get rid of parentheses
16H^2+10H+H-84=0
We add all the numbers together, and all the variables
16H^2+11H-84=0
a = 16; b = 11; c = -84;
Δ = b2-4ac
Δ = 112-4·16·(-84)
Δ = 5497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{5497}}{2*16}=\frac{-11-\sqrt{5497}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{5497}}{2*16}=\frac{-11+\sqrt{5497}}{32} $
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